Potências 2 - Resolução
From Matemática
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| − | 3. Pretende-se simplificar a fração $\displaystyle \frac{x^{-7}\times x^{2}}{(-3 x)^{2}}$.
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| − | Como $a^{p}\times a^{q}=a^{p+q}$ vem $$\displaystyle \frac{x^{-7}\times x^{2}}{(-3 x)^{2}}=\frac{x^{-7+2}}{\left(-3\right)^{2}\times x^{2}}=\frac{x^{-5}}{\left(-3\right)^{2}\times x^{2}}.$$
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| − | Uma vez que $\displaystyle \frac{a^{p}}{a^{q}}=a^{p-q}$, resulta
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| − | $$\frac{x^{-5}}{\left(-3\right)^{2}\times x^{2}}=\frac{x^{-5-2}}{\left(-3\right)^{2}}=\frac{x^{-7}}{9}.$$
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| − | Assim
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| − | $$\displaystyle \frac{x^{-7}\times x^{2}}{(-3 x)^{2}}=\frac{x^{-7}}{9}=\frac{1}{9 \, x^{7}}.$$
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| − | [[Potências 2|Voltar]]
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Latest revision as of 15:52, 8 January 2013
