Resposta 7
From Matemática
Revision as of 11:40, 16 November 2012 by Paula.oliveira (Talk | contribs)
7. Para $n$ par, $\displaystyle g_n=\frac{-n+1}{n^3+1}$ e para $n$ ímpar, $\displaystyle g_n=\frac{n+1}{n^3+1}$. Como $\displaystyle \lim \frac{-n+1}{n^3+1} = \lim \frac{n+1}{n^3+1} =0$, resulta que $\lim g_n=0$.
