Resposta 11
From Matemática
11. Procedendo à divisão de $n+1$ por $n+4$, obtemos $\displaystyle \frac{n+1}{n+4}=1+\frac{-3}{n+4}$. Logo $$\displaystyle \lim \left( \frac{n+1}{n+4} \right) ^n= \lim \left[ \left( 1+\frac{-3}{n+4} \right)^{n+4} \cdot \left( 1+\frac{-3}{n+4} \right)^{-4} \right]= e^{-3} \cdot 1^{-4}=e^{-3}.$$
